The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
& Y" [; q& F0 F% E# }4 a- k. |/ ?
4 V' A" w7 L5 X* c5 i* lStarting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. 公仔箱論壇$ A1 t# O1 A! t) [2 @
7 n% }) m2 W3 L7 S公仔箱論壇Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.) Z( ^" x, i% G; l: K0 Z5 d
www1.tvboxnow.com$ S2 _! n/ v2 _) k6 b
#3 did the obvious choice 40 divided by 2 =20, so he picked 20
+ Y+ \/ ]# N" `* D/ \+ X" ~9 Itvb now,tvbnow,bttvbTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% o# {, [9 {) X4 n3 T# {3 {$ G
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.公仔箱論壇& O0 R6 s* l4 b. F1 X2 a9 n
公仔箱論壇: D1 H4 Y) M5 H3 C
#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。4 ]2 X( q- ~6 g0 X0 X! |7 y
tvb now,tvbnow,bttvb# l' Q6 e' V0 x
Ended all have the same number and all died. |