That is a very simple mathematics question.
. A9 C5 c& l" F8 S" jtvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child
8 L* t2 a- B+ _; r5 K$ ]tvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1, h7 ` S4 q* ~2 M4 ?( l
x + y + z = 100 Formula 2
6 X! l$ u. E' y' n# uSimplify Formula 2 into z, we get z = 100 - x - y Formula 3+ r2 x' ~9 B% o7 X1 P- _
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4. V8 w- L; x. l. U! ~) T
Formula 4 can change into 11x + 5y = 100 Formula 5
3 V- _4 ?% l, H* y0 S' r. z; ~ [9 yTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
# k. h! M( t6 ?0 ]& j! i& k) A7 aAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
; a( B N5 e( k) F公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |