That is a very simple mathematics question.tvb now,tvbnow,bttvb Z2 H2 q7 O- x& e5 z, d
Let x = Male, y = Female, z = Child
( @9 N$ [' ?: B0 i: {( Y ~tvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1
D: N& d8 S2 y: \公仔箱論壇x + y + z = 100 Formula 2
. i0 ], G9 u$ B A( a+ b1 ?& Mtvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
1 U) d# n: r( Gwww1.tvboxnow.comSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4www1.tvboxnow.com; E# |5 q2 d* E5 k. W" T4 L2 Q
Formula 4 can change into 11x + 5y = 100 Formula 5
- r- A2 t& t2 V+ M- tIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.www1.tvboxnow.com8 W4 u' D7 a) @/ H6 R
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
. u& G/ Z! m% a+ J$ i( tEventually, the answer is 20 female and 80 children and no male. |