That is a very simple mathematics question.www1.tvboxnow.com- s6 |% U/ U4 p9 Y0 T$ F* y" @
Let x = Male, y = Female, z = Child J# M: \/ u, p# z' { C
6x + 3y + z/2 = 100 Formula 1www1.tvboxnow.com+ w" o+ j" L* j/ s: }1 l
x + y + z = 100 Formula 2
( f3 c- r& {5 ~tvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
( j2 h; j9 e- v) D# Ntvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4www1.tvboxnow.com7 E- i# P. c B1 B9 N$ C
Formula 4 can change into 11x + 5y = 100 Formula 5
! h: G l. f O: N0 g8 h* l公仔箱論壇In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.& e+ f1 I, V# J) Y0 y8 X9 ^( t, |
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
1 f1 m0 p4 o0 X; C0 M! u$ @' ?2 l4 zEventually, the answer is 20 female and 80 children and no male. |