That is a very simple mathematics question.
: T3 A# D: |7 J# a4 D& MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child$ \. o4 v, P3 [: K3 d
6x + 3y + z/2 = 100 Formula 1
- s: J5 n& y& {tvb now,tvbnow,bttvbx + y + z = 100 Formula 2tvb now,tvbnow,bttvb% K F4 G# B# W/ g1 L- H0 Y
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3www1.tvboxnow.com& e& [) u8 J. i8 i5 b3 b# B! e: V+ I
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4+ }5 [7 b7 ^, h2 L
Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇, y$ u/ p& ?* |9 o7 `# x# t+ ]
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
* i9 U5 H. e' X& l9 |& F$ J公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
- s3 N) l4 J; i6 cEventually, the answer is 20 female and 80 children and no male. |