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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
5 `& }9 {; r5 P+ g- w" S- E: S2 jwww1.tvboxnow.com1st u divide the ball into two group (i group 6 ball)
1 J# P; ]5 B. z' ]# }* Y  twww1.tvboxnow.comthen 称 them c which side is the heavy   j$ I" V6 d7 u
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group www1.tvboxnow.com/ T% E8 H! G0 a2 q  r
if not balance take the heavy and then www1.tvboxnow.com/ `  n( g7 T& M
take the heavy group divided into 2 group i group contain 1 ball than 称 it 1 y7 l$ ^8 W$ |, _. h4 J8 e
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb1 V) e4 `* t( f, x7 Z0 f# Y7 }  g
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
9 }1 L9 f& q8 \公仔箱論壇然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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