hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
0 S: g4 i: a  i2 N* H1st u divide the ball into two group (i group 6 ball)
+ {0 |; Y5 x* G( Z+ ^5 Ltvb now,tvbnow,bttvbthen 称 them c which side is the heavy tvb now,tvbnow,bttvb& p# w; m% b' k3 U
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
3 M+ e2 _1 O1 V3 ~if not balance take the heavy and then
/ p" x7 A" T) z  Y7 h- ~www1.tvboxnow.comtake the heavy group divided into 2 group i group contain 1 ball than 称 it / c# k% R$ t% \* k
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
+ L6 ]; H. a0 E- |4 ~（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
6 E9 V3 L8 n8 j2 c: ?然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me