hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^  Q; s6 _5 V8 D7 S
1st u divide the ball into two group (i group 6 ball)tvb now,tvbnow,bttvb" ~8 ~1 w/ S  m: _# \
then 称 them c which side is the heavy
/ D2 i* v1 ]9 }then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb4 F; Z% R7 h! \  r& J; Y  f/ Q& _
if not balance take the heavy and then
; b4 H9 |$ d3 G2 M3 B0 ywww1.tvboxnow.comtake the heavy group divided into 2 group i group contain 1 ball than 称 it & g4 c1 R, `  V" A4 _
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
* s1 q4 k7 U& J& Otvb now,tvbnow,bttvb（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
% F* o8 Z' f2 N" e3 ?www1.tvboxnow.com然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me