zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
) z/ |- g# s! i/ {+ y公仔箱論壇将比较重的那份再平均分成两份成一次$ O3 v* N, o/ Q7 j# w# G# N7 c" A
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
. C8 C* @* d2 U+ W* Xif  (4v4)= same that means the rest of 4 is got more weight1 Y! B* t% I; H- t9 M0 a; t
    then goto 2 - compare rest of(4)  - 2 with 2
7 ?( u8 A9 V6 T0 o           if (left side is more weight)公仔箱論壇5 w9 I' p% s1 l) {+ C
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
8 E- F: y; T+ j4 Cwww1.tvboxnow.com          else ( right side is more weight)0 V5 |! P! X# O1 R: @- O+ o; _* w
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
9 M# ?3 H! l! J2 P9 S$ aelse ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。