The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
5 K% t7 F$ F* r o, [( E) T( [' D
6 Q$ ^7 u" x& E, I l6 K; B! F; I' ^Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. www1.tvboxnow.com6 C! `3 ]* S( E3 ^
' X N6 a: Y2 r( ztvb now,tvbnow,bttvbNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.& L+ G. @0 k |( p
S% `: ^% {- `. b#3 did the obvious choice 40 divided by 2 =20, so he picked 20
9 g3 B; {) K9 s2 }1 G8 `www1.tvboxnow.com
d6 L K H$ H4 b1 pTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
4 V( w) _" f7 x5 v7 b4 PTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
* P; j2 D; D/ l" S: V* cTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.www1.tvboxnow.com% t( M; f( L, `8 w
公仔箱論壇9 e6 A; w# I( J% [" g+ l# Y" \
Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
